((5x)/(x-2))+(3/x)+2=6/(x^2-2x)

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Solution for ((5x)/(x-2))+(3/x)+2=6/(x^2-2x) equation: 



((5x)/(x-2))+(3/x)+2=6/(x^2-2x)

We move all terms to the left:

((5x)/(x-2))+(3/x)+2-(6/(x^2-2x))=0



Domain of the equation: (x-2))!=0

x∈R





Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: (x^2-2x))!=0

x∈R



We add all the numbers together, and all the variables

(5x/(x-2))+(+3/x)-(6/(x^2-2x))+2=0

We get rid of parentheses

(5x/(x-2))+3/x-(6/(x^2-2x))+2=0

We calculate fractions

We do not support expression: x^3

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